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Solution:Highest number divisible by 3 lesser than 100 is 99Smallest number divisible by 3 greater than 200 is 201Number of digits divisible by 3 between 100 and 200 is= (201/3) – (99/3)= 66 -33= 33
201 divided by 3 is NOT 66,it's 67!Hence the answer is 34.
201 isn't included in the range. The range is from 100 to 200, or in multiples of 3, 102-198. The answer is A.
There's a better way of thinking:From 100 to 130 there are 10 numbers divisible by 3 (3's Multiplication table).So, from 100 to 190 there are 30!.From 190 to 200 there are 3 more (192,195 and 198).Tihs way, you have 3*10+3 = 33.
MISTAKE SHOULD BE CORRECTED AS FOLLOWSHighest number divisible by 3 lesser than 100 is 99Smallest number divisible by 3 LESSER than 200 is 198Number of digits divisible by 3 between 100 and 200 is= (198/3) – (99/3)= 66 -33= 33
by taking another way of thinking......198 , the last number lesser than 200 is 66th number divisible by 3.102, the first number higher than 100 is 34th number divisible by 3. MEANS we have 33 nos. lesser than 100 which is divisible by 3.Thus, the total number of integers between 100 and 200 that are divisible by 3 = 66-33=33
thank you Ashwini
Solution:
ReplyDeleteHighest number divisible by 3 lesser than 100 is 99
Smallest number divisible by 3 greater than 200 is 201
Number of digits divisible by 3 between 100 and 200 is
= (201/3) – (99/3)
= 66 -33
= 33
201 divided by 3 is NOT 66,it's 67!Hence the answer is 34.
ReplyDelete201 isn't included in the range. The range is from 100 to 200, or in multiples of 3, 102-198. The answer is A.
ReplyDeleteThere's a better way of thinking:
ReplyDeleteFrom 100 to 130 there are 10 numbers divisible by 3 (3's Multiplication table).
So, from 100 to 190 there are 30!.
From 190 to 200 there are 3 more (192,195 and 198).
Tihs way, you have 3*10+3 = 33.
MISTAKE SHOULD BE CORRECTED AS FOLLOWS
ReplyDeleteHighest number divisible by 3 lesser than 100 is 99
Smallest number divisible by 3 LESSER than 200 is 198
Number of digits divisible by 3 between 100 and 200 is
= (198/3) – (99/3)
= 66 -33
= 33
by taking another way of thinking......
ReplyDelete198 , the last number lesser than 200 is 66th number divisible by 3.
102, the first number higher than 100 is 34th number divisible by 3. MEANS we have 33 nos. lesser than 100 which is divisible by 3.
Thus, the total number of integers between 100 and 200 that are divisible by 3 = 66-33=33
thank you Ashwini
ReplyDelete